9m^2+51m+70=0

Solution for 9m^2+51m+70=0 equation:

9m^2+51m+70=0

a = 9; b = 51; c = +70;
Δ = b2-4ac
Δ = 512-4·9·70
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-9}{2*9}=\frac{-60}{18}
=-3+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+9}{2*9}=\frac{-42}{18}
=-2+1/3
$